Stoichiometry Calculator
Calculate mole ratios, mass-to-mass conversions, limiting reagents, theoretical yields, and percent yields for balanced chemical reactions. Enter reactant amounts to determine product quantities — essential for chemistry students, lab technicians, and chemical engineers.
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What is Stoichiometry?
Stoichiometry is the quantitative relationship between reactants and products in a chemical reaction, governed by the balanced chemical equation. The coefficients in a balanced equation represent mole ratios: in 2H₂ + O₂ → 2H₂O, two moles of hydrogen react with one mole of oxygen to produce two moles of water. These ratios enable calculation of exact reactant and product quantities.
Stoichiometric calculations are fundamental to chemistry — they determine how much of each reactant is needed, which reactant runs out first (limiting reagent), how much product can theoretically be formed (theoretical yield), and how efficient the reaction was (percent yield). This calculator handles all these calculations from the mole ratios you provide.
적용 수학 공식 및 방정식
이 Stoichiometry Calculator는 5가지 핵심 수학 공식을 사용합니다:
1 Mole Ratio Conversion ▼
For 2H₂ + O₂ → 2H₂O: 3 moles H₂ produces 3 × (2/2) = 3 moles H₂O.
2 Moles from Grams ▼
36 grams of water (H₂O, MW=18): Moles = 36 / 18 = 2 moles.
3 Theoretical Yield ▼
Determines the maximum possible product from the limiting reagent.
Explore all calculation options on the 비율 계산기 home page.
비율 계산기 사용법
이 비율 계산기는 아래의 3단계로 쉽게 사용할 수 있습니다:
수치 입력하기
입력 칸에 알고 있는 비율 값을 입력합니다. 구하려는 미지수 자리의 칸 하나는 비워둡니다.
모드 선택하기
비율 모드(풀기, 간소화, 스케일링)를 선택합니다. 각 모드는 입력한 수치에 맞춰 다른 공식들을 적용합니다.
결과 확인하기
계산하기 버튼을 누릅니다. 결과 화면에 정답과 함께 시각적인 비율 바, 원형 차트, 상세한 단계별 풀이 과정이 출력됩니다.
실제 예제 문제 및 단계별 풀이
비율 계산기를 활용하여 아래 3가지 예제 문제를 단계별로 해결하는 과정입니다:
입력 1 How much O₂ needed to react with 4 moles H₂?
입력 2 Theoretical yield from 10g CH₄ burning in excess O₂
입력 3 Find limiting reagent: 5 mol H₂ and 4 mol O₂
자주 묻는 질문 (FAQ)
What is stoichiometry? ▼
Stoichiometry is the branch of chemistry that deals with the quantitative relationships between reactants and products in chemical reactions. It uses the coefficients in balanced equations to determine mole ratios, which enable calculation of how much of each substance is needed or produced.
How do I calculate moles from grams? ▼
Moles = Mass (grams) ÷ Molar Mass (g/mol). For example, 36g of water (H₂O): Molar mass = 2(1.008) + 16.00 = 18.016 g/mol. Moles = 36 ÷ 18.016 = 2.0 moles. The molar mass is the sum of atomic masses of all atoms in the formula.
What is a limiting reagent? ▼
The limiting reagent is the reactant that is completely consumed first, determining the maximum amount of product that can form. The other reactant(s) are in excess. To find it: convert all reactants to moles, divide each by its coefficient — the smallest value indicates the limiting reagent.
What is theoretical yield? ▼
Theoretical yield is the maximum amount of product that can be formed from the limiting reagent, assuming 100% conversion and no losses. It is calculated using stoichiometry: moles of limiting reagent × mole ratio × product molar mass.
What is percent yield? ▼
Percent yield = (Actual Yield ÷ Theoretical Yield) × 100. It measures reaction efficiency. Real reactions rarely achieve 100% due to side reactions, incomplete conversion, and purification losses. A 90%+ yield is considered excellent in most contexts.
How do I use mole ratios? ▼
Mole ratios come from balanced equation coefficients. In 2H₂ + O₂ → 2H₂O, the ratio of H₂ to O₂ is 2:1, and H₂ to H₂O is 2:2 (1:1). To find moles of product: moles of reactant × (product coefficient ÷ reactant coefficient).
What is the molar mass and how do I find it? ▼
Molar mass is the mass of one mole of a substance in grams. Find it by adding the atomic masses (from the periodic table) of all atoms in the formula. NaCl: 22.99 + 35.45 = 58.44 g/mol. Ca(OH)₂: 40.08 + 2(16.00) + 2(1.008) = 74.10 g/mol.
How do stoichiometry and the conservation of mass relate? ▼
The conservation of mass states that matter is neither created nor destroyed. Stoichiometry ensures this is satisfied: the total mass of reactants equals the total mass of products. A balanced equation guarantees equal atoms on both sides, which guarantees equal mass.
Can I do stoichiometry with volumes of solutions? ▼
Yes. For solutions, moles = Molarity (mol/L) × Volume (L). A 0.5M HCl solution in 0.250L contains 0.125 mol HCl. Use this moles value in stoichiometric calculations just like moles calculated from mass.
What is excess reagent? ▼
The excess reagent is the reactant that remains after the limiting reagent is fully consumed. The amount of excess remaining = initial moles − moles consumed (calculated stoichiometrically from the limiting reagent). Converting this to grams gives the mass of unreacted excess.